120=20t+(1/2)(10)t^2

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Solution for 120=20t+(1/2)(10)t^2 equation: 


t in (-oo:+oo)

120 = 10*(1/2)*t^2+20*t // - 10*(1/2)*t^2+20*t

120-(10*(1/2)*t^2)-(20*t) = 0

120-5*t^2-20*t = 0

120-5*t^2-20*t = 0

DELTA = (-20)^2-(-5*4*120)

DELTA = 2800

DELTA > 0

t = (2800^(1/2)+20)/(-5*2) or t = (20-2800^(1/2))/(-5*2)

t = (20*7^(1/2)+20)/(-10) or t = (20-20*7^(1/2))/(-10)

t in { (20*7^(1/2)+20)/(-10), (20-20*7^(1/2))/(-10) }

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